Anodo:
2H2O --> 4H+ + 4e- + O2(g)
O2 : e- = 1 : 4
e- = O2 * 4/1
O2 = PV/RT
O2= (554/760)*(6.05) / (0.082)*(38+273) = 0.173 mol
e- = 0.17 mol * 4/1 = 0.69 mol
Catodo:
Ag+ + 1e- --> Ag(s)
Ag : e- = 1 : 1
Ag = e- = 0.69 mol
PA(Ag) = 107.9 g/mol
Ag = 0.69mol * PA
Ag= 74.6g
Ultima modifica di DNAnna; 02-08-2012 a 11:50 AM
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