View Single Post
  #2 (permalink)  
Vecchio 10-04-2012, 07:56 PM
DNAnna DNAnna non è in linea
Senior Member
 
Registrato dal: Nov 2011
Messaggi: 568
predefinito

2CO2 <-- --> 2CO + O2
__1__________________
1 - 2x_________2x___x__ = 1 - 2x + 2x + x = 1 + x = 1.05 ==> x = 1.05 - 1 = 0.05 atm
=
0.9____________0.1__0.05.
=> Kp1 = 0.05 * 0.1^2 / 0.9^2 = 6.17*10^-4

2CO2 <-- --> 2CO + O2
__1__________________
1 - 2x_________2x___x__ = 1 - 2x + 2x + x = 1 + x = 1.35 ==> x = 1.35 - 1 = 0.35 atm
=
0.3____________0.7__0.35.
Kp2 = 0.35 * 0.7^2 / 0.3^2 = 1.905

dH°r = dH°f(O2) + 2*dH°f(CO) - 2*dH°f(CO2) = 0 - 2*26.41 + 2*94.05 = 135.28 Kcal(?)
van't hoff:
Ln Kp2/Kp1 = dH°r / R * (1/T1 - 1/T2)
1/T2 = 1.63*10^-3
T2 = 614.6K = 341.5°C
Rispondi quotando